Answer
$$-\left(x-6\right)^2-10$$
Work Step by Step
Completing the square to put the equation in vertex form, we find:
$$-\left(x^2-12x+46\right)\\ -\left(\left(x-6\right)^2+46-\left(-6\right)^2\right) \\ -\left(x-6\right)^2-10$$
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