Answer
$$x=0,\:x=-5,\:x=-1,\:x=1$$
Work Step by Step
Solving the equation by isolating $x$ with the quadratic formula, we find:
$$0=x\left(x^3+5x^2-x-5\right) \\ x\left(x+5\right)\left(x+1\right)\left(x-1\right)=0 \\ x=0,\:x=-5,\:x=-1,\:x=1$$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 6 Rational Exponents and Radical Functions - 6.5 Graph Square Root and Cube Root Functions - 6.5 Exercises - Mixed Review - Page 451: 47
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