Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 6 Rational Exponents and Radical Functions - 6.5 Graph Square Root and Cube Root Functions - 6.5 Exercises - Mixed Review - Page 451: 43

Answer

$$x=\frac{4\sqrt{7}}{7},\:x=-\frac{4\sqrt{7}}{7}$$

Work Step by Step

Solving the equation by isolating $x$, we find: $$7x^2=16 \\ x^2=\frac{16}{7} \\ x=\sqrt{\frac{16}{7}},\:x=-\sqrt{\frac{16}{7}} \\ x=\frac{4\sqrt{7}}{7},\:x=-\frac{4\sqrt{7}}{7}$$
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