Answer
See below.
Work Step by Step
$\frac{f(x)}{g(x)}=\frac{4x^2-x}{2x^2}=\frac{4x^2}{2x^2}-\frac{x}{2x^2}=2-\frac{1}{2x}$
The denominator of the fraction cannot be zero, thus $x\ne0$. Therefore, the domain is the set of real numbers apart from $x=0$.
