Answer
See below.
Work Step by Step
We need to show that $f(g(x))=x=g(f(x))$
$f(g(x))=f(\sqrt[3]{\frac{x}{5}})=5(\sqrt[3]{\frac{x}{5}}^3)=5\frac{x}{5}=x$
$g(f(x))=g(5x^3)=\sqrt[3]{\frac{5x^3}{5}}=\sqrt[3]{x^3}=x$
Thus we proved what we had to.