Answer
$$y=\sqrt[4]{\frac{x+49}{9}},\:y=-\sqrt[4]{\frac{x+49}{9}}$$
Work Step by Step
Switching the elements of the domain and the range (in other words, the dependent and independent variables), we find that the inverse is:
$$x=9y^4-49 \\ y=\sqrt[4]{\frac{x+49}{9}},\:y=-\sqrt[4]{\frac{x+49}{9}}$$