Answer
$$y=\sqrt{x+16},\:y=-\sqrt{x+16}$$
Work Step by Step
Switching the elements of the domain and the range (in other words, the dependent and independent variables), we find that the inverse is:
$$x=y^2-16 \\ y=\sqrt{x+16},\:y=-\sqrt{x+16}$$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 6 Rational Exponents and Radical Functions - 6.4 Use Inverse Functions - 6.4 Exercises - Quiz for Lessons 6.3-6.4 - Page 445: 14
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