Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - 5.6 Find Rational Zeroes - 5.6 Exercises - Mixed Review - Page 377: 66

Answer

See below

Work Step by Step

The discriminant is $b^2-4ac$. Substitute $a=81\\b=18\\c=1$ into this: $(18)^2-4(81)(1)=0$ The discriminant is zero; thus the equation has only one real solution.
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