Answer
$x=\frac{7}{2} \lor x=\frac{1}{4}$
Work Step by Step
Given: $8x^2-30x+7=0$
The equation now becomes: $(2x-7)(4x-1)=0$
We have: $2x-7=0 \lor 4x-1=0$
Solve for x: $2x=7 \lor 4x=1$
Then, $x=\frac{7}{2} \lor x=\frac{1}{4}$
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