Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - 5.6 Find Rational Zeroes - 5.6 Exercises - Mixed Review - Page 377: 61

Answer

$X=\begin{bmatrix} \frac{31}{10}& -\frac{14}{5}& -\frac{19}{5}\\ \frac{9}{10}& -\frac{6}{5} & \frac{-6}{5} \end{bmatrix}$

Work Step by Step

Multiply the inverse of the matrix on the left by the matrix on the right: $X=\begin{bmatrix} 2& -8\\3 &-7 \end{bmatrix}^{-1}\begin{bmatrix} -1 & 4& 2\\ 3& 0 &-3 \end{bmatrix}\\=\frac{1}{-14+24}\begin{bmatrix} -7 &8\\ -3 & 2 \end{bmatrix}\begin{bmatrix} -1 & 4& 2\\ 3& 0 &-3 \end{bmatrix}\\=\frac{1}{10}\begin{bmatrix} 7+24 &-28 & -14-24\\ 3+6 & -12 & -6-6 \end{bmatrix}\\=\frac{1}{10}\begin{bmatrix} 31& -28 & -38\\ 9 & -12 & -12 \end{bmatrix}\\=\begin{bmatrix} \frac{31}{10}& -\frac{14}{5}& -\frac{19}{5}\\ \frac{9}{10}& -\frac{6}{5} & \frac{-6}{5} \end{bmatrix}$
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