Answer
$$x=\frac{-5\pm 2\sqrt{10}}{3}$$
Work Step by Step
We first check that the function is in the form $ax^2+bx+c$. Then, using the quadratic formula, we obtain:
$$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$
$$x=\frac{-10\pm \sqrt{(10)^2-4(3)(-5)}}{2(3)}$$
$$x=\frac{-5\pm 2\sqrt{10}}{3}$$
