Answer
$$x=-\frac{1}{2},\:x=-\frac{3}{2}$$
Work Step by Step
Completing the square, we find:
$$4\left(x^2+2x+\frac{3}{4}\right) \\ 4\left(\left(x+1\right)^2+\frac{3}{4}-1^2\right) \\ 4\left(x+1\right)^2-1 \\ x=-\frac{1}{2},\:x=-\frac{3}{2}$$
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