Chapter 4 Quadratic Functions and Factoring - Chapter Test - Page 323: 2

See the graph

Given: $y=-(x+3)^2+5$ $y=-x^2-6x-4$ The x-coordinate is $x=\frac{-b}{2a}=\frac{-(-6)}{2.(-1)}=-3$ Substitute for x to find the y-coordinate: $y=-(-3)^2-6(-3)-4=5$ Hence, the vertex is $(-3,5)$. The axis of symmetry is $x=-3$. Make a list of values: $x=-6 \rightarrow y=-4$ $x=0 \rightarrow y=-4$ $x=-7 \rightarrow y=-11$ $x=1 \rightarrow y=-11$