Answer
$\frac{ac-bd}{c^2+d^2}-\frac{bc+ad}{c^2+d^2}i$
Work Step by Step
$\frac{a-bi}{c+di}=\frac{(a-bi)(c-di)}{(c+di)(c-di)}=\frac{ac-bd-(bc+ad)i}{c^2+d^2}=\frac{ac-bd}{c^2+d^2}-\frac{bc+ad}{c^2+d^2}i$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 4 Quadratic Functions and Factoring - 4.6 Perform Operations with Complex Numbers - 4.6 Exercises - Skill Practice - Page 280: 64
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