Answer
$|4+3i|=5$
Work Step by Step
The absolute value of a complex number
$z=a+bi,$ denoted $|z|,$ is a nonnegative
real number defined as $|z|=\sqrt{a^{2}+b^{2}}$.
$|z|=|4+3i|$
$=\sqrt{a^{2}+b^{2}}\qquad$ ...substitute $4$ for $a$ and $3$ for $b$
$=\sqrt{4^{2}+3^{2}}\qquad$ ...simplify.
$=\sqrt{16+9}$
$=\sqrt{25}\qquad$ ...evaluate.
$=5$
