Chapter 3 Linear Systems and Matrices - 3.4 Solve Systems of Linear Equations in Three Variables - 3.4 Exercises - Skill Practice - Page 182: 5

The given ordered triple is a solution of the system.

$(6,0,-3)$ $x+4y-2z=12$ $1(6)+4(0)-2(-3)=12$ $6+0+6=12$ $12=12$ $3x-y+4z=6$ $3(6)-1(0)+4(-3)=6$ $18-0-12=6$ $6=6$ $-x+3y+z=-9$ $-1(6)+3(0)+1(-3)=-9$ $-6+0-3=-9$ $-9=-9$