Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - 3.4 Solve Systems of Linear Equations in Three Variables - 3.4 Exercises - Skill Practice - Page 182: 10

Answer

$x=-3$ $y=-1$ $z=-1$

Work Step by Step

Using elimination for the first two equations: $2x - y + 2z = -7$ $-x + 2y - 4z =5$ Multiply both sides of the first equation by $2$: $4x - 2y + 4z = -14$ $-x + 2y - 4z =5$ __________________________ $3x=-9$ $x=-3$ Then continue to use elimination for the first and third equations: $2x - y + 2z = -7$ $x+4y-6z=-1$ Multiply both sides of the first equation by $3$: $6x - 3y + 6z = -21$ $x+4y-6z=-1$ _____________________ $7x+y=-22$ Substitute $x=-3$: $7(-3)+y=-22$ $y=-1$ Solve for z: $-(-3) + 2(-1) - 4z =5$ $-4z=4$ $z=-1$
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