Answer
See below
Work Step by Step
Since the sum of the triangle is $180^\circ$, we obtain:
$$A+B+C=180^\circ\\A=180^\circ-A-B\\A=180^\circ -98^\circ -37^\circ\\A=45^\circ$$
Use law of sines to find:
$$\frac{a}{\sin A}=\frac{b}{\sin B}\\ b=\frac{a}{\sin A}\times \sin B\\b\approx 25.2^\circ$$
$$\frac{c}{\sin C}=\frac{a}{\sin A}\\c=\frac{a}{\sin A}\times \sin C\\c\approx15.3^\circ$$