Answer
See below
Work Step by Step
The sequence is geometric with first term $a_2=8$ and common ratio $r=4$. We obtain: $$a_n=a_2r^{n-2}\\a_n=8\times4^{n-2}\\a_n=2\times4^{n-1}$$
The first 6 terms are $a_1=2\\a_2=8\\a_3=32\\a_4=128\\a_5=512\\a_6=2048$
