Answer
See below
Work Step by Step
The sequence is geometric with first term $a_2=6$ and common ratio $r=2$. So, a rule for the nth term is:$$a_n=a_2r^{n-2}=6.(2)^{n-2}=3*2^{n-1}$$
The first 6 terms are $a_1=3\\a_2=6\\a_3=12\\a_4=24\\a_5=48\\a_6=96$