Chapter 12 Sequences and Series - 12.3 Analyze Geometric Sequences and Series - 12.3 Exercises - Skill Practice - Page 814: 32

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The sequence is geometric with first term $a_5=1$ and common ratio $r=\frac{1}{8}$. So, a rule for the nth term is:$$a_n=a_5r^{n-5}=1\times(\frac{1}{8})^{n-5}=\frac{1}{8}^{n-5}$$ The first 6 terms are $a_1=4096\\a_2=512\\a_3=64\\a_4=8\\a_5=1\\a_6=0.125$