Answer
See below
Work Step by Step
The sequence is geometric with first term $a_3=75$ and common ratio $r=5$. We obtain: $$a_n=a_3r^{n-3}\\a_n=75\times5^{n-3}$$
The first 6 terms are $a_1=3\\a_2=15\\a_3=75\\a_4=375\\a_5=1875\\a_6=9375$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 12 Sequences and Series - 12.3 Analyze Geometric Sequences and Series - 12.3 Exercises - Skill Practice - Page 814: 34
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