Answer
Axis of symmetry: x=0
Vertex: (0,11)
Work Step by Step
$y = -4x^{2} + 11 $
The standard form for a quadratic equation is
$y = ax^{2} + bx + c$ So a= -4, b= 0, and c= 11
Axis of symmetry:
The formula for axis of symmetry is
$x= \frac{-b}{2a}$
$x= \frac{-(0)}{2(-4)}$
$x= \frac{0}{-8}$
x=0
Vertex:
Plug in the x value of the axis of symmetry to find the y value of the vertex.
$y = -4x^{2} + 11 $
$y = -4(0)^{2} + 11 $
y= 0 + 11
y=11
The vertex is (0,11)
