Answer
Axis of symmetry: x=4
Vertex: (4,-23)
Work Step by Step
$y = x^{2} - 8x - 7 $
The standard form for a quadratic equation is
$y = ax^{2} + bx + c$ So a= 1, b= -8, and c= -7
Axis of symmetry:
The formula for axis of symmetry is
$x= \frac{-b}{2a}$
$x= \frac{-(-8)}{2(1)}$
$x= \frac{8}{2}$
x=4
Vertex:
Plug in the x value of the axis of symmetry to find the y value of the vertex.
$y = x^{2} - 8x - 7 $
$y = (4)^{2} - 8(4) - 7 $
y= 16 - 32 - 7
y= -23
The vertex is (4,-23)
