Answer
a) Please see the graph.
b) 16 feet
c) No, the ball traveled 48 more feet between $t=1$ and $t=2$ than $t=0$ and $t=1$
Work Step by Step
a) The graph was made using graphing software.
b)
$h=-16t^2+72$
$h=-16(1)^2+72$
$h=-16*1+72$
$h=-16+72$
$h=56$
$72-56 = 16$
c)
$h=-16t^2+72$
$h=-16(2)^2+72$
$h=-16*4+72$
$h=-64+72$
$h=8$
$72-8=64$
$64-16=48$