Answer
Option E
Work Step by Step
This quadratic's equation is f(x)=$ax^{2}+c$.
Given the equation f(x)=$-x^{2}+2$.
The a value is -1 and since it is negative, the graph opens downwards (⋂) Therefore, it has a maximum.
We calculate the maximum.
Since there is no horizontal translation the maximum y-value is at f(0)
f(0)= $-(0)^{2}$ +2
f(0) = +2
The vertex is (0, 2)
