Answer
Option A
Work Step by Step
This quadratic's equation is f(x)=$ax^{2}+c$.
Given the equation f(x)=$-3x^{2}+8$.
The a value is -3 and since it is negative, the graph opens downwards (⋂) Therefore, it has a maximum.
We calculate the maximum.
Since there is no horizontal translation the maximum y-value is at f(0)
f(0)= $-3(0)^{2}$ + 8
f(0) = +8
The vertex is (0, 8)
