Answer
$6y(10y^{2}-7)(y-5)$
Work Step by Step
Given :
$6y(10y^{3}-50y^{2}-7y+35)$
This becomes :
$=6y(10y^{2}(y-5)-7(y-5))$
$=6y((10y^{2}-7)(y-5))$
$=6y(10y^{2}-7)(y-5)$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 520: 32
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