Answer
$4c(c+5)(c+8)$
Work Step by Step
Given expression :
$4c(c^{2}+13c+40)$
Now $1.40 = 8.5$
Therefore, break the $13c$ term as $(8c+5c)$
This becomes:
$=4c(c^{2}+5c+8c+40)$
$=4c(c(c+5)+8(c+5))$
$=4c((c+8)(c+5))$
$=4c(c+5)(c+8)$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 520: 29
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