Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - Chapter Review - 7-1 Zero and Negative Exponents - Page 464: 9

Answer

$\frac{q^4}{p^2}$

Work Step by Step

We write the expression given as a division problem: $1\div p^2q^{-4}r^0$ The negative exponent rule states that for every nonzero number $a$ and integer $n$, $a^{-n}=\frac{1}{a^n}$. We use this rule to rewrite the expression: $\frac{1}{1}\div\frac{p^2r^0}{q^4}$ To divide fractions, we multiply by the reciprocal: $\frac{1}{1}\div\frac{q^4}{p^2r^0}$ We multiply the numerators and the denominators: $\frac{q^4}{p^2r^0}$ The zero as an exponent rule states that for every nonzero number $a$, $a^0=1$. We use this to rewrite the expression as: $\frac{q^4}{p^2\times1}=\frac{q^4}{p^2}$
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