Answer
-$\frac{20}{9}$
Work Step by Step
$\frac{2x}{y^{2}z^{-1}}$, where x = 2, y = -3, z = -5
$\frac{2(2)}{-3^{2}-5^{-1}}$
$\frac{4}{9(-5^{-1})}$
Here, -5$^{-1}$ will be moved to the numerator and the -1 will change to simply 1:
$\frac{(4)(-5^{1})}{9}$ = $\frac{(4)(-5)}{9}$ = $\frac{-20}{9}$
