Answer
$45$
Work Step by Step
We rewrite the given expression as a division problem: $5x^0\div y^{-2}$
The zero as an exponent rule states that for every nonzero number $a$, $a^0=1$. Since $x^0=1$, and anything multiplied by $1$ is itself, we can remove that term.
$5\div y^{-2}$
The negative exponent rule states that for every nonzero number $a$ and integer $n$, $a^{-n}=\frac{1}{a^n}$. We use this rule to rewrite the expression:
$\frac{5}{1}\div\frac{1}{y^2}$
To divide by a fraction, we multiply by the reciprocal: $5\times y^2$
We plug in the value for $y$: $5(-3)^2$
We simplify powers: $5(9)$
We multiply: $45$
