Answer
$\frac{4y^8}{x^2}$
Work Step by Step
We write the expression given as a division problem: $4x^{-2}\div y^{-8}$
The negative exponent rule states that for every nonzero number $a$ and integer $n$, $a^{-n}=\frac{1}{a^n}$. We use this rule to rewrite the expression:
$\frac{4}{x^2}\div\frac{1}{y^8}$
To divide fractions, we multiply by the reciprocal: $\frac{4}{x^2}\times\frac{y^8}{1}$
We multiply the numerators and the denominators: $\frac{4y^8}{x^2}$
