Answer
Increase
$f(-2)= y= 1/64$
$f(-1)=y=1/8$
$f(0)=y=1$
$f(1)=y=8$
$f(2)=y=64 $
$f(3)=y=512$
Work Step by Step
$f(-2)= y=8^{-2} = 1/8^2 = 1/64$
$f(-1)=y=8^{-1} =1/8$
$f(0)=y=8^0 =1$
$f(1)=y=8^1=8$
$f(2)=y=8^2 =64 $
$f(3)=y=8^3=512$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 7 - Exponents and Exponential Functions - 7-6 Exponential Functions - Practice and Problem-Solving Exercises - Page 451: 35
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