Answer
$f(-2) = \frac{4}{25}$
$f(-1)=\frac{2}{5}$
$f(0) = 1$
$f(1) = 2.5$
$f(2) = 6.25$
$f(3) = 15.625$
The values of the range increase as the values of the domain increase.
Work Step by Step
We know that $a^{-n} = \frac{1}{a^n}$
$f(-2) = 2.5^{-2} = \frac{1}{2.5^2} = \frac{1}{6.25} = \frac{4}{25}$
$f(-1) = 2.5^{-1} = \frac{1}{2.5}=\frac{2}{5}$
$f(0) = 2.5^0 = 1$
$f(1) = 2.5^1 = 2.5$
$f(2) = 2.5^2 = 6.25$
$f(3) = 2.5^3 = 15.625$
The values of the range increase as the values of the domain increase.
