Answer
$f(-2) = 100$
$f(-1) =10$
$f(0) = 1$
$f(1) = 0.1$
$f(2) = 0.01$
$f(3) = 0.001$
The values of the range increase as the values of the domain decrease.
Work Step by Step
We know that $a^{-n} = \frac{1}{a^n}$
$f(-2) = 0.1^{-2} = \frac{1}{0.1^2} = \frac{1}{0.01} = 100$
$f(-1) = 0.1^{-1} = \frac{1}{0.1}=10$
$f(0) = 0.1^0 = 1$
$f(1) = 0.1^1 = 0.1$
$f(2) = 0.1^2 = 0.01$
$f(3) = 0.1^3 = 0.001$
The values of the range increase as the values of the domain decrease.
