Answer
$\frac{1}{8}$
Work Step by Step
The given expression : $\frac{(2^{4})^{3}}{2^{15}}=$ $\frac{2^{12}}{2^{15}}$ ,
(since $(a^{m})^{n}=$ $a^{mn}$)
This can be written as : $2^{12}$ X $2^{-15}$
(since $a^{-1}=$ $\frac{1}{a}$)
Thus, this becomes : $2^{-3}=$ $\frac{1}{8}$
