Answer
$4 \times 10^{-5}$
Work Step by Step
$\dfrac{a^m}{a^n}=a^{m-n}, a\ne0$
Divide the corresponding parts while using the rule above to find:
$=\dfrac{3.6}{9} \times \dfrac{10^{-10}}{10^{-6}}
\\=0.4 \times 10^{-10-(-6)}
\\=0.4 \times 10^{-10+6}
\\=0.4 \times 10^{-4}
\\=(4 \cdot 10^{-1}) \times 10^{-4}
\\=4 \times 10^{-1+(-4)}
\\=4 \times 10^{-5}$
