Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - 7-5 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 444: 36

Answer

$\dfrac{32x^5}{243y^5}$

Work Step by Step

RECALL: (i) $\left(\dfrac{x}{y}\right)^n=\dfrac{x^n}{y^n}, y \ne 0$ (ii) $(xy)^m = x^my^m$ Use the rules above to have: $=\dfrac{2^5x^5}{3^5y^5} \\=\dfrac{32x^5}{243y^5}$
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