Answer
$\dfrac{1}{32}$
Work Step by Step
RECALL:
(i) $\left(\dfrac{x}{y}\right)^n=\dfrac{x^n}{y^n}, y \ne 0$
(ii) $(xy)^m = x^my^m$
(iii) $(a^m)^n=a^{mn}$
(iv) $\dfrac{a^m}{a^n} = a^{m-n}$
Use the rules above to have:
$=(2^{2-3})^5
\\=(2^{-1})^5
\\=2^{-1(5)}
\\=2^{-5}
\\=\dfrac{1}{2^5}
\\=\dfrac{1}{32}$
