Answer
$9$
Work Step by Step
RECALL:
(i) $(a^m)^n = a^{mn}$
(ii) $(ab)^m=a^mb^m$
(iii) $a^m \cdot a^n =a^{m+n}$
(iv) $a^0=1, a\ne0$
(v) $a^{-m} = \dfrac{1}{a^m}$
Use rule (i) above to obtain:
$=3^{7\cdot2} (3^{-4\cdot3})
\\=3^{14} (3^{-12})$
Use rule (iii) above to obtain:
$=3^{14+(-12)}
\\=3^{2}
\\=9$
