Chapter 7 - Exponents and Exponential Functions - 7-4 More Multiplication Properties of Exponents - Practice and Problem-Solving Exercises - Page 437: 34

$9a^{6}b^{8}$

The given expression : $(3b^{-2})^{2}(a^{2}b^{4})^{3}$ Now, $(ab)^{n} = a^{n}b^{n}$ Hence, $(3b^{-2})^{2}$ = $9$ X $b^{-4}$ and $(a^{2}b^{4})^{3}$ = $a^{6}$ X $b^{12}$ Thus,the expression becomes : $9$ X $b^{-4}$ X $a^{6}$ X $b^{12}$ This becomes : $9$ X $b^{-4+12}$ X $a^{6}$ Final result : $9a^{6}b^{8}$