Answer
$-8a^9b^6$
Work Step by Step
RECALL:
(i) $(a^m)^n = a^{mn}$
(ii) $(ab)^m=a^mb^m$
(ii) $a^m \cdot a^n =a^{m+n}$
(iv) $a^0=1, a\ne0$
Use rule (i) and rule (ii) above to obtain:
$=(-2)^3a^{2\cdot3}b^3 \cdot a^3b^3
\\=-8a^6b^3 \cdot a^3b^3$
Use rule (iii) above to have:
$=-8a^{6+3}b^{3+3}
\\=-8a^9b^6$
