Answer
$\dfrac{1}{a}$
Work Step by Step
(i) $a^m \cdot a^n = a^{m+n}$
(ii) $a^{-m} = \dfrac{1}{a^m}, a \ne 0$
Use the rules above to obtain:
$=\dfrac{1}{a^{4+(-3)}}
\\=\dfrac{1}{a^{1}}
\\=\dfrac{1}{a}$
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