Answer
$x^4$
Work Step by Step
(i) $a^m \cdot a^n = a^{m+n}$
(ii) $a^{-m} = \dfrac{1}{a^m}, a \ne 0$
Use the rules above to obtain:
$=\dfrac{1}{x^{3+(-7)}}
\\=\dfrac{1}{x^{-4}}
\\=\dfrac{1}{\frac{1}{x^4}}
\\=1 \cdot \dfrac{x^4}{1}
\\=x^4$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 7 - Exponents and Exponential Functions - 7-3 Multipying Powers with the Same Base - Practice and Problem-Solving Exercises - Page 430: 58
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