Answer
$4y^{5}$ + $8y^{2}$
Work Step by Step
The area of a parallelogram, Area = $base$ X $height$
Hence , Area = $4y^{2}$ X $(y^{3}+2)$
By distributive property, Area = $4y^{2}$ X $y^{3}+ 4y^{2}$ X $2$
This becomes : Area = $4y^{2+3}$ + $8y^{2}$
(since the exponents are added while multipliying with the same base)
Final result : Area = $4y^{5}$ + $8y^{2}$
