Answer
$\dfrac{z^2+5z-24}{3z^2+6z}$
Work Step by Step
Given: $\dfrac{z-3}{3z} \times \dfrac{z+8}{z+2}$
$\dfrac{z-3}{3z} \times \dfrac{z+8}{z+2}=\dfrac{(z-3)(z+8)}{3z(z+2)}$
$=\dfrac{z^2+8z-3z-24}{3z^2+6z}$
$=\dfrac{z^2+5z-24}{3z^2+6z}$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 11 - Rational Expressions and Functions - Mid-Chapter Quiz - Page 678: 8
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