Answer
$6(x-2); x \ne -2$
Work Step by Step
Given: $\dfrac{6x^2-24}{x+2}$
Need to find the common factors of the given expression.
$\dfrac{6x^2-24}{x+2}=\dfrac{6(x^2-4)}{x+2}$
$=\dfrac{6(x+2)(x-2)}{x+2}$
If we put $x=-2$ then denominator becomes zero, which cannot be possible.
After simplification, we get
$=6(x-2); x \ne -2$
