Answer
$\dfrac{(2a-1)}{(a-3)^2(a+2)}$
Work Step by Step
Given: $\dfrac{(2a-1)}{(a-3)} \times \dfrac{1}{a^2-a+6}$
$=\dfrac{(2a-1)}{(a-3)(a-3)(a+2)}$
$=\dfrac{(2a-1)}{(a-3)^2(a+2)}$
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