Answer
$\dfrac{1}{7(d+1)}$
Work Step by Step
Given: $\dfrac{(4d^2-3d)}{7d} \times \dfrac{1}{4d^2+d-3}$
$=\dfrac{d(4d-3)}{7d(4d-3)(d+1)}$
$=\dfrac{1}{7(d+1)}$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 11 - Rational Expressions and Functions - Mid-Chapter Quiz - Page 678: 12
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